Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
3y + 2/4 =7 First, you subtract 2/4 (1/2) from both sides, resulting in 3y = 13/2 (6 and a half) Then, you multiply both sides by 1/3 (which is the same as dividing by 3), giving you y=13/6.
-3
L = P/2 - W.
1/2
Better formatting is cos(2x+20)=-0.5
If you mean: y = 3/4x-0.5 then the perpendicular equation could be y = -4/3x-5
Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
3y + 2/4 =7 First, you subtract 2/4 (1/2) from both sides, resulting in 3y = 13/2 (6 and a half) Then, you multiply both sides by 1/3 (which is the same as dividing by 3), giving you y=13/6.
x/2 + 6 = 2x (Multiply by 2) x + 12 = 4x (Subtract x) 12 = 3x (Divide by 3) x = 4 (Check it) 4/2 + 6 = 2 x 4 2 + 6 = 8
-3
L = P/2 - W.
1/2
This gives us the equation: A = hb/2 + c To solve for c, we simply subtract hb/2 from each side! A - hb/2 = c c = A - hb/2
Half correct because x = 2 and y = 6
The statement that represent that is one - half a number is 267.
(0,-3)