To factor the expression ( B^2 + 6y + 1 ), we look for two numbers that multiply to the constant term (1) and add up to the linear coefficient (6). However, since the product of two numbers that adds up to 6 while multiplying to 1 is not possible with real numbers, the expression does not factor neatly over the integers. Thus, it remains in its original form or can be solved using the quadratic formula if needed.
6y + 5y = -66 11y = -66 (-66/11 = y) y = -6
6y=5y+2y 6y=7y that does't work its unequal -
5x + 6y + 3y - 2x you have to add like terms. add the y terms and then the x terms 9y + 3x this is your answer
(A) x + 6y = 19 (B) -x + 6y = 17 (A)+(B): 12y = 36 so that y = 3 Substituting this value of y in (A), x + 18 = 19 so x = 1.
It's 0
10y= 6y+5+3y 10y=6+9y y=6
6y + 5y = -66 11y = -66 (-66/11 = y) y = -6
6y=5y+2y 6y=7y that does't work its unequal -
5x + 6y + 3y - 2x you have to add like terms. add the y terms and then the x terms 9y + 3x this is your answer
(A) x + 6y = 19 (B) -x + 6y = 17 (A)+(B): 12y = 36 so that y = 3 Substituting this value of y in (A), x + 18 = 19 so x = 1.
x=6y-4x=-2y+28Substitute (6y-4) for x in the second equation and solve for y:6y-4=-2y+288y=32y=4Then solve for x:x=6(4)-4=20(20,4)
y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
Not sure if you mean 7x 6y as in 7*6y=126, where * means "multiplied by" and you must solve for y or if you mean that we must solve for both x and y, but the answer to the part where you are solving 7*6y=126 is 3.
It's 0
6y = 12x+32 Divide all terms by 6: y = 2x+5 and 1/3 which is now in slope intercept form
4x+6y=62 -6x+6y=-18 what is the ordered pair
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.