221 256 - 229 = 221 227
To solve the equation (x^2 - 256 = 0), we can rewrite it as (x^2 = 256). Taking the square root of both sides gives us two solutions: (x = 16) and (x = -16). Therefore, there are two unique values of (x) that solve the equation.
4m2-256 = 0 Add 256 to both sides: 4m2 = 256 Divide both sides by 4: m2 = 64 Square root both sides to find the value of m: m = 8 Alternatively, if 4m is to be squared, and not just the m: (4m)2 - 256 = 0 16m2 - 256 = 0 16m2 -256 + 256 = 256 16m2 = 256 16m2/16 = 256/16 m2 = 16 √m2 = √16 m = ±4
There is only one solution: 44 = 256.
0.9846
1 times 256.
64
Half of 256 is 128 - whether to a division problem or any other.
A fraction is essentially a division problem:256/1000= 256 ÷ 1,000 = 0.256
221 256 - 229 = 221 227
To solve the equation (x^2 - 256 = 0), we can rewrite it as (x^2 = 256). Taking the square root of both sides gives us two solutions: (x = 16) and (x = -16). Therefore, there are two unique values of (x) that solve the equation.
4m2-256 = 0 Add 256 to both sides: 4m2 = 256 Divide both sides by 4: m2 = 64 Square root both sides to find the value of m: m = 8 Alternatively, if 4m is to be squared, and not just the m: (4m)2 - 256 = 0 16m2 - 256 = 0 16m2 -256 + 256 = 256 16m2 = 256 16m2/16 = 256/16 m2 = 16 √m2 = √16 m = ±4
There is only one solution: 44 = 256.
0.0312
down 4531 across 256
0.9846
You have enough information to obtain two equations. 1. You know that when the two liquids are added together, you need 400L total. 2. You also know that the 80% acid times its volume plus 30% acid times its volume must equal 62% times the 400L. 3. Write the two equations. Let x = volume 80% acid & y = volume 30% acid. Therefore from (1) above: x + y = 400; equation A From (2) above: .8x + .3y = .62*400; equation B 4. You have two equations, two unknowns. Solve for x & y. 5. Multiply equation A by -.8 and add equations A & B. Note x adds out to 0. Equation A now becomes -.8x - .8y = -.8*400 or -.8x - .8y = -320. -.8x - .8y = -320 +.8x + .3y = 248 (note .62*400 = 248) So -.5y = -72 and divide both sides by -.5 which yields y = 144. 6. Use equation A to solve for x since we now know "y"; x + 144 = 400 or x = 256. 7. Answer: 256L of 80% acid & 144L of 30% acid.