answersLogoWhite

0

What else can I help you with?

Related Questions

What multplication problem has a product of 256?

1 times 256.


How do you solve 256 divided by4?

64


What is the half of 256 to a division problem?

Half of 256 is 128 - whether to a division problem or any other.


How do you write 256 over 1000 as a decimal?

A fraction is essentially a division problem:256/1000= 256 ÷ 1,000 = 0.256


What is the answer to math problem 221 256 - 229?

221 256 - 229 = 221 227


How many unique values of x solve x2-256 equals 0?

To solve the equation (x^2 - 256 = 0), we can rewrite it as (x^2 = 256). Taking the square root of both sides gives us two solutions: (x = 16) and (x = -16). Therefore, there are two unique values of (x) that solve the equation.


How do you solve 4m squared minus 256 equals 0?

4m2-256 = 0 Add 256 to both sides: 4m2 = 256 Divide both sides by 4: m2 = 64 Square root both sides to find the value of m: m = 8 Alternatively, if 4m is to be squared, and not just the m: (4m)2 - 256 = 0 16m2 - 256 = 0 16m2 -256 + 256 = 256 16m2 = 256 16m2/16 = 256/16 m2 = 16 √m2 = √16 m = ±4


How many numbers between 100 and 400 can be expressed as powers of 4 answer and solution?

There is only one solution: 44 = 256.


What is 256 divided by 8?

0.0312


What is power lines 1 solution level 5?

down 4531 across 256


How do you solve the answer to 2.56 divided by 2.6?

0.9846


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L solution that is 62 percent acid?

You have enough information to obtain two equations. 1. You know that when the two liquids are added together, you need 400L total. 2. You also know that the 80% acid times its volume plus 30% acid times its volume must equal 62% times the 400L. 3. Write the two equations. Let x = volume 80% acid & y = volume 30% acid. Therefore from (1) above: x + y = 400; equation A From (2) above: .8x + .3y = .62*400; equation B 4. You have two equations, two unknowns. Solve for x & y. 5. Multiply equation A by -.8 and add equations A & B. Note x adds out to 0. Equation A now becomes -.8x - .8y = -.8*400 or -.8x - .8y = -320. -.8x - .8y = -320 +.8x + .3y = 248 (note .62*400 = 248) So -.5y = -72 and divide both sides by -.5 which yields y = 144. 6. Use equation A to solve for x since we now know "y"; x + 144 = 400 or x = 256. 7. Answer: 256L of 80% acid & 144L of 30% acid.