one way is to let x^2=m, then you have an equation m^2+3m-28=0, and then you solve this quadratic equation for m, and you get:
m=4, or m=-7... since m represents x^2, m can only be positive (if we are dealing with real numbers), so m=-7 is not possible solution...
now if m=4, the x^2=4, and solving this equation: x=2 or x=-2
First you must square the 6 which the answer is 36. Then you subtract 36 from 8 and the answer is negative 28. Finally you solve negative 28 minus 28 (-28-28) which equals negative 56 (-56).
62
the question is 2-5(h+3)=-28. and i know that h=3but im not sure how you would solve this problem
Yes that is correct
30
75
It is: 26
Divide 28 by 4. X = 7
1 x 10^28
Does it say solve for y?
28/100 minus 1 1/3 equals -1 4/75
If 6y-8 = 28 then y = 6