x + 5y = 10 is not a question or a problem, so it doesn't need a solution,
and it doesn't have one.
It's the equation of a straight line, and the (x, y) coordinates of every point
on the line satisfy the equation.
There's no such thing as a single number for 'x' and a single number for 'y'
until you have another equation in addition to this one.
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
The Commutative Property of Addition.
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
(4, -1)
-x + 5y = 10 5y= 11 y = 11/5
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
you cant
24
The Commutative Property of Addition.
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
(20 - x)/5
what is the solution of x-5y=10 and 2x-10y=20
If: 20x+5y = 15 Then: y = -4x+3
8 + 5y = 18 Therefore, 5y = 10 y = 10/5 y = 2
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7