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The problem is a quadratic.
Rewritten as x2-x+5=0
Since this cannot be factored, the quadratic formula can be used.
I can tell there will be imaginary numbers because the discriminant is < 0
b2-4ac = 1-4(1)(5) = -19
(1±(√12-4(1)(5)))/2(1) = confusing = 1/2 ± i√19
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How do you solve 3x squared plus 5x minus 25 equals 0?
x = 25 / 3squared + 5
If x squared minus y squared equals 10 and x plus y equals 5 what is x minus y?
2
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X2 - 4X - 5 = 0 easy factor, what two factors of - 5 add up to - 4 (X + 1)(X - 5) X = - 1 ------------- X = 5 --------------
What does x equal when x squared minus 17x equals 60?
5 or 12
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(x-5)(x+3)
How do you solve 3x squared plus 5x minus 25 equals 0?
x = 25 / 3squared + 5
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You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve
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2
Three squared minus 2 squared equals?
It is: 9-4 = 5
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X squared equals 25 solve for x?
5.
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What does x equal when x squared minus 17x equals 60?
5 or 12
Solve x squared - 2x - 10 equals 5?
(x-5)(x+3)
Can you solve the equation x squared plus 2x minus 5 equals 0?
Yes and its solutons are: x = -1 -sq rt of 6 and x -1 +sq rt of 6
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
How do you solve x plus 3 plus 6 equals 4?
minus 5
