0
(1) y = x + 3
(2)-2x + y = -4
It is usual to present the equations showing one unknown expressed in terms of the other unknown. This is already the case in Equation (1).
Restructuring Equation (2) gives y = 2x -4
(1) y = x + 3
(3) y = 2x - 4 Now subtract Equation (1) from Equation (3) to eliminate y.
y - y = 2x - x -4 -3 : 0 = x - 7 : x = 7
Substitute for x in Equation (1)
y = 7 + 3 : y = 10
What else can I help you with?
Solve 2x plus 3 equals 7?
2x+3 = 7 2x = 7-3 2x = 4 x = 2
How do you solve 3x plus 4 equals 2x - 3?
3x+4 = 2x-3 3x-2x = -3-4 x = -7
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
How do you solve 2x plus 3 equals 9X equals?
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
Solve for x 2x plus two thirds equals five thirds?
2x + 2/3= 5/3 2x= 3/3 2x=1 x=1/2
Solve 2x plus 3 equals 9?
3
Solve 2x plus 3 equals 7?
2x+3 = 7 2x = 7-3 2x = 4 x = 2
How do you solve 4x plus 3 equals -3 plus 2x plus 14?
4x + 3 = -3 + 2x + 14 2x + 3 = -3 +14 2x + 3 = 11 2x = 8 x=4
How do you solve 2x plus 3 equals negative 11?
2x+3 = -11 2x = -11-3 2x = -14 x = -7
How do you solve 3x plus 4 equals 2x - 3?
3x+4 = 2x-3 3x-2x = -3-4 x = -7
How do you solve 7x plus 3y equals 30 -2x plus 3y equals 3 in an order pair?
(3,3)
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
How do you solve the equation 3x-2 equals 2x plus 3?
3x-2 = 2x+3 3x-2x = 3+2 x = 5
How do you solve 2x plus 3 equals 9X equals?
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
How do you solve x plus 2x equals 3?
2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3
Solve 2x plus 3 equals 9 x equals?
2x+3=9x 3=9x-2x 3=7x x=3/7
Solve for x 2x plus two thirds equals five thirds?
2x + 2/3= 5/3 2x= 3/3 2x=1 x=1/2
