You test if the last two digits are divisible by 4.
If the digit in the tens' place is odd, the digit in the units place must be 2 or 6.
If the digit in the tens' place is even, the digit in the units place must be 0, 4 or 8.
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No; as 4 is less than 7321694 it cannot be divisible by it. Nor is 7321694 divisible by 4. There are two tests for divisibility by 4 that I can offer. First (test given in most books): If the last two digits of the number (as a number) are divisible by 4 then so is the original number. Second (much easier test): add twice the tens digit to the ones digit; if this sum is divisible by 4 then so is the original number. Using second test, for 7321694: 2x9 + 4 = 22 which is not divisible by 4, so 7321694 is not divisible by 4. The second test can be repeated until a single digit remains; if this single digit is 4 or 8, then the original number is divisible by 4. otherwise not: 7321694 → 2x9 + 4 = 22 22 → 2x2 + 2 = 6 → not 4 or 8, so original number is not divisible by 4.
All numbers are not divisible by 3. In order to test if a number is a prime, you first test to see if it ends in a 2, 4, 6, 8, or 0. In that case it is divisible by 2 and not a prime. The next number you use for your test is 3. More odd numbers are divisible by 3 than by any other odd number but it is only the second number used for the test. You continue testing until you reach the square root of the number. If the number is only divisible by itself and one, it is prime. 3 is only the second test number in the division test for primes.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
Yes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.
You could combine the tests for divisibility by 3 and 4. To test for divisibility by three, add all the digits together and see if they're divisible by three. If necessary, you can keep repeating the addition until you come up with a single-digit number. To test for divisibility by four, take the last two digits. If that two-digit number is divisible by four, then the whole number is. This is because any multiple of 100 is divisible by 4, so only the last two digits matter. Combined, these two tests will allow you to quickly check for divisibility by 12.