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The area of a square is the square of the side (all sides of a square are of equal lengths). So taking the square root of the area would give the value of one side in linear units. Now adjacent sides of a square form a right angle. Therfore the hypotenuse would be the square root of (side^2 + side^2) but you know the value of the side from the previous step when you took the square of the area. Hence you can find the hypotenuse.
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How do you find the area of a right triangle when you have the base and hypotenuse?
Use Pythagoras' theorem: hypotenuse2-base2 = height2 and then square root this to give the actual height 1/2*base*height = area
Can you find the length of the hypotenuse of a right angled triangle with an area of XXIIII square inches and a height of VIII inches giving details of your work?
First find the length of the base: base = area times 2 divided by height base = 24 times 2 divided by 8 = 6 inches Then use Pythagoras' Theorem to find length of the hypotenuse: base2 + height2 = hypotenuse2 62 + 82 = 100 square inches. Square root of 100 = 10 inches. Therefore the length of the hypotenuse is X inches.
Can you use the tangent ratio to find the length of the hypotenuse?
No; the tangent ratio only deals with the lengths of the opposite side and adjacent side. You can square the two sides and add them together, then find the square root of the sum to find the length of the hypotenuse.
What is the length of the hypotenuse of a triangle if the length of one side is 6 m and the other side 8 m?
To find the length of the hypotenuse on a triangle, you have to use the Pythogoras Theoram. using the equation a square + b square = c square. you cannot find it without using the pythagoras theoram
In a 45-45-90 triangle the legs are 7 how do you find the hypoteuse?
Use Pythagoras' theorem: a2+b2 = c2 (the hypotenuse) 72+72 = 98 square units. The square root of 98 = 9.899494937 units (the hypotenuse)
