Suppose that each time the game is played you win an amount X, with probability p or lose an amount Y with probability (1-p). To start with it is assumed that you cannot draw a game. Then each time the game is played you expect to win X with a probability p and lose Y (= win -Y) with probability (1-p). Therefore, the expected gain for you, each time the game is played, is X*p - Y*(1-p). The game is fair if this value is 0. If it is greater than 0 the game is biased in your favour. Otherwise it is biased against you. You can easily incorporate multiple outcomes - such as with a lottery: a bigger win for getting more numbers. If X(1), X(2), ... X(n) are the n pay-outs to you (remember that what you pay will be a negative number), and P(1), p(2), ... p(n) are their respective probabilities where the sum of all the p(r) = 1, then your expected win per game is X(1)*p(1) + X(2)*p(2) + ... + X(n)*p(n) and the game is fair if this is 0.
win
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
MY guess would be that it is not Minute to win it but "in it to win it" this meaning that the reason you are there is to win. Hope this answere ur question :)
n2 + n = n(n + 1)
it depends do it starting from cove then on your way down. make sure you beat n. tropy first DO NOT USE CHEATS TO GET YOURE CHARACTERS GET THEM NORMALLYIF YOU USE ACTION REPLAY UNLOCK ALL AWARDS IT IS IMPOSSIBLE TO GET HIM there is a cheat on gameshark check that out
Tropy Elbląskie's population is 120.
The population of Tropy Sztumskie is 210.
Strong number is a number for which sum of factorials of the digits is equal to the given number. Eg: let us consider 145 where sum of factorials of the digits= 1!+4!+5!=1+24+120=145 i,e., the given number. c program for strong number is: #include<stdio.h> #include<conio.h> void main() { int sof=0,n,dn,ctr,prod,rem; printf("Enter the number\n"); scanf("%d",&n); dn=n; while(n!=0) { prod=1,ctr=1; rem=n%10; while(ctr<=rem) { prod=prod*ctr; ctr=ctr+1; } sof=sof+prod; n=n/10; } if(sof==dn) { printf("The number entered is strong number"); } else { printf("The number entered is not a strong number"); } } By Nagarjuna sri indu ECE, IBP.
import java.io.*; public class Wave{ public static void main (String args[])throws IOException{ BufferedReader dataIn = new BufferedReader (new InputStreamReader(System.in)); String aa; int type, wave, ctr, ctr2 ; System.out.println("Select wave Type (1 or 2) : "); System.out.println("Input wave type: "); aa = dataIn.readLine(); type = Integer.parseInt(aa); String cc; System.out.println("How many number of waves do you want?"); System.out.println("Input wave count: "); cc = dataIn.readLine(); wave = Integer.parseInt(cc); while(wave>0){ for (ctr=0; ctr<=6; ctr++){ for (ctr2=0; ctr2<=ctr; ctr2++){ System.out.print("*"); } System.out.print("\n"); } if(type == 2){ for(ctr=6; ctr>0; ctr--){ for(ctr2=ctr; ctr2>0; ctr2--){ System.out.print("*"); } System.out.print("\n"); } } wave--; } } }
import java.io.*; public class Wave{ public static void main (String args[])throws IOException{ BufferedReader dataIn = new BufferedReader (new InputStreamReader(System.in)); String aa; int type, wave, ctr, ctr2 ; System.out.println("Select wave Type (1 or 2) : "); System.out.println("Input wave type: "); aa = dataIn.readLine(); type = Integer.parseInt(aa); String cc; System.out.println("How many number of waves do you want?"); System.out.println("Input wave count: "); cc = dataIn.readLine(); wave = Integer.parseInt(cc); while(wave>0){ for (ctr=0; ctr<=6; ctr++){ for (ctr2=0; ctr2<=ctr; ctr2++){ System.out.print("*"); } System.out.print("\n"); } if(type == 2){ for(ctr=6; ctr>0; ctr--){ for(ctr2=ctr; ctr2>0; ctr2--){ System.out.print("*"); } System.out.print("\n"); } } wave--; } } }
The address of the Rvc Conservancy is: 53 N Park Ave Ste 51, Rockville Ctr, NY 11570-4111
Opasnye tropy - 1954 is rated/received certificates of: Finland:K-8
#include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #define p printf #define s scanf int ctr,x,n,nmod; char cont; main() { do { clrscr(); ctr=0; p ("Input a number: "); s ("%d", &n); if (n<0) p ("\nINVALID NUMBER"); else if (n==0n==1) p ("\nNEITHER PRIME NOR COMPOSITE"); else if (n>1) { for (x=1; x<=n; x++) { nmod=n%x; if (nmod==0) ctr+=1; } if (ctr==2) p ("\nPRIME"); else p ("\nCOMPOSITE"); } p ("\n\nDo you wish to continue [Y/N]? "); cont=getche(); } while (cont=='Y'cont=='y'); }
You need to make sure you max your potions (well as max as your level can take) as there is no heal between fights, I recommend using a class that does have healing and stun abilities, and always take Tropy out first, since it does the most damage.
for (int ctr = 0; ctr <= 9; ctr++) Response.Write(ctr + ' ');
Strong number:-The sum of the factorials of digits of a number is equal to the original number.Ex: n=145=> 1! + 4! + 5! = 1 + 24 + 120 = 145so it is strong number.Armstrong number:-The sum of the cubes of digits of a number is equal to the original number.Ex: n=153 => 13 + 53 +33 = 1+125+27= 153so 153 is arm strong number.C program for strong numbers#include#includevoid main(){int sof=0,n,dn,ctr,prod,rem;printf("Enter the number\n");scanf("%d",&n);dn=n;while(n!=0){prod=1,ctr=1;rem=n%10;while(ctr