As a product of its prime factors: 3*3*7*7 = 441
It is: 3*3*7*7 = 441
As a product of its prime factors: 3*3*7*7 = 441
7)441 7)63 3)9 3)9 3)3 = 1 Hence 441 is the product of 7x7x3x3 = 7^(2) x 3^(2) = (7 x3)^(2) = 21^(2)
3 x 3 x 7 x 7
3 x 3 x 7 x 7 = 441
It is: 3*3*7*7 = 441
As a product of its prime factors: 3*3*7*7 = 441
As a product of its prime factors: 3*3*7*7 = 441 Its square root is 21 or as 3*7 as the product of its prime factors
It is: 3, 3, 7 and 7
441 = 3 x 3 x 7 x 7
441 = 3 x 3 x 7 x 7
As a product of its prime factors: 3*3*7*7 = 441
To find the highest common factor (HCF) of 441 and 1575, we need to factorize both numbers. The prime factorization of 441 is 3^2 x 7^2, and the prime factorization of 1575 is 3^2 x 5^2 x 7. To find the HCF, we take the product of the common prime factors raised to the lowest power they appear in both factorizations, which is 3^2 x 7 = 63. Therefore, the highest common factor of 441 and 1575 is 63.
Well, let's take a moment to appreciate the beauty of numbers coming together. The highest common factor of 441 and 945 is 63. It's like finding a happy little tree in a forest of numbers, bringing harmony and balance to our mathematical landscape.
42240 is not prime because it can go into other numbers besides 1 and 42240.
3 x 3 x 7 x 7