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There are two things you need to remember. First, given a line y=mx+b, where m is the slope and b is the y-intercept, the slope of the line perpendicular is going to be -1/m. Next, if you have the point where the lines cross, you want to use the point-slope form of a line to get the equation of the perpendicular line. Suppose the lines cross at (h,k). Then the point-slope form of the equation for the perpendicular line crossing at (h,k) will be (y-k)=-1/m(x-h). This can be brought into the slope-intercept form y=(-1/m)x + h/m + k.

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