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How do you work out the perimeter and interior angles of a right angle triangle when its height is 7.04 cm greater than its base and has an area of 297.3696 square cm?
First the height and base of the triangle must be found so let the height be (x+7.04) and the base be x:-
1/2*height*base = area
1/2*(x+7.04)*x = 297.3696 cm2
Multiply both sides by 2 and multiply out the brackets:
x2+7.04x = 594.7392
Subtract 594.7329 from both sides thus forming a quadratic equation:
x2+7.04-594.7392 = 0
Solving the above by means of the quadratic equation formula gives x a positive value of 21.12
Therefore: height = 28.16 cm and base = 21.12 cm
Use Pythagoras' theorem to find the third side which will be the hypotenuse:
28.162+21.122 = 1239.04 and the square root of this is 35.2
Therefore the perimeter = 28.16+21.12+35.2 = 84.48 cm
Use any of the trigonometrical ratios to find the interior angle:
tan-1(28.16/21.12) = 53.13010235 or 53 degrees to the nearest degree
Therefore the interior angles are 53 degrees, 37 degrees and 90 degrees
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no
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If the area of triangle B is 64 times greater than the area of triangle A how much greater is the perimeter of triangle B?
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What is the perimeter of a triangle with an area of 924cm?
It can be anything greater than 3200.8 cm. By making the triangle taller and thinner you can keep the area constant while increasing the perimeter - without limit.
What is the perimeter and interior angles of a right angle triangle when its height is 7 cm greater than its base and has an area of 60 square cm?
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no
Which of these two regular polygons has the largest interior angle triangle or heptagon?
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The three interior angles of a triangle can only be Acute or Obtuse. However, the external component of these three angles is reflex.
What triangle has a reflex angle?
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