Q: How do you work out the prime factors of 700?

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As a product of its prime factors: 2*2*5*5*7 = 700

The prime factors of 700 are 2 x 2 x 5 x 5 x 7 (or 22 x 52 x 7)

As a product of its prime factors: 2*2*5*5*7 = 700

The prime factors are: 2 x 2 x 5 x 5 x 7

Find the prime factors of each. Prime factors of 10 are 2 and 5 Prime factors of 15 are 3 and 5 Multiply one number by the prime factors unique to the other: 10x3 or 15x2 =30

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As a product of its prime factors: 2*2*5*5*7 = 700

2, 5 and 7

As a product of its prime factors: 2*2*5*5*7 = 700

700=2x2x5x5x7

The factors of 700 are: 1 2 4 5 7 10 14 20 25 28 35 50 70 100 140 175 350 700The prime factors of 700 are: 2 5 7

The prime factors of 700 are 2 x 2 x 5 x 5 x 7 (or 22 x 52 x 7)

To find the highest common factor (HCF) of 30, 210, and 700, you can use the prime factorization method. Prime Factorization: Prime factorize each number: 30 = 2 * 3 * 5 210 = 2 * 3 * 5 * 7 700 = 2^2 * 5^2 * 7 Identify Common Prime Factors: Identify the common prime factors among the numbers: 2, 3, 5, and 7. Multiply Common Prime Factors: Multiply the common prime factors: 2 * 3 * 5 * 7 = 210 Therefore, the HCF of 30, 210, and 700 is 210.

Multiply prime numbers or prime factors to find their product.

As a product of its prime factors: 2*2*5*5*7 = 700

I assume you are asking how do you work out the factors of a prime number. A prime number by definition only has itself and 1 as factors.

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Either one will work. If you're listing factors, use factors. If you're using prime factorization, use prime factors.