As a product of its prime factors: 2*2*5*5*7 = 700
The prime factors of 700 are 2 x 2 x 5 x 5 x 7 (or 22 x 52 x 7)
As a product of its prime factors: 2*2*5*5*7 = 700
The prime factors are: 2 x 2 x 5 x 5 x 7
Find the prime factors of each. Prime factors of 10 are 2 and 5 Prime factors of 15 are 3 and 5 Multiply one number by the prime factors unique to the other: 10x3 or 15x2 =30
As a product of its prime factors: 2*2*5*5*7 = 700
2, 5 and 7
As a product of its prime factors: 2*2*5*5*7 = 700
700=2x2x5x5x7
The factors of 700 are: 1 2 4 5 7 10 14 20 25 28 35 50 70 100 140 175 350 700The prime factors of 700 are: 2 5 7
The prime factors of 700 are 2 x 2 x 5 x 5 x 7 (or 22 x 52 x 7)
Multiply prime numbers or prime factors to find their product.
To find the highest common factor (HCF) of 30, 210, and 700, you can use the prime factorization method. Prime Factorization: Prime factorize each number: 30 = 2 * 3 * 5 210 = 2 * 3 * 5 * 7 700 = 2^2 * 5^2 * 7 Identify Common Prime Factors: Identify the common prime factors among the numbers: 2, 3, 5, and 7. Multiply Common Prime Factors: Multiply the common prime factors: 2 * 3 * 5 * 7 = 210 Therefore, the HCF of 30, 210, and 700 is 210.
As a product of its prime factors: 2*2*5*5*7 = 700
I assume you are asking how do you work out the factors of a prime number. A prime number by definition only has itself and 1 as factors.
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Either one will work. If you're listing factors, use factors. If you're using prime factorization, use prime factors.