The area of a sphere is equal to its circumference times its diameter.
There are a variety of ways to work out this formula, most of them involving calculus.
(See the links for the volume of a sphere).
Yes. Second contribution: Surface area of sphere = XXXVI = 36 square inches. When all the working out is done, which the previous contributor has failed to do, the answer is: Volume of the sphere = 20.311 cubic inches correct to three decimal places. This was achieved by rearranging the formula (4*pi*r2) for finding the surface area of the sphere in order to find its radius. The radius was then used in the formula (4/3*pi*r3) for finding the volume of the sphere.
To calculate the surface area of a rectangular shape, you need to know the length and width of the rectangle. The formula for the surface area is given by multiplying the length by the width (Surface Area = Length × Width). If you're calculating the surface area of a rectangular prism, you would sum the areas of all six faces, which can be calculated using the formula: Surface Area = 2(length × width + length × height + width × height).
In a diffusion test, a sphere with a surface area to volume ratio of 2.1 m⁻¹ would demonstrate a more efficient diffusion process compared to solids with lower ratios. The higher ratio indicates that there is more surface area available for the substance to diffuse across relative to its volume, facilitating faster mass transfer. Consequently, we would expect the sphere to reach equilibrium more quickly than models with lower surface area to volume ratios. Overall, the efficiency of diffusion in the sphere would be enhanced due to its geometric properties.
It would help if the question was less obscure. What do you mean by "work"? How the surface area affects chemical processes (for example the surface area of catalysts), or diffusion, or surface areas and friction?
Approximately 546.1 ft2. To show work, The volume is 4/3 piR^3 and surface area is 4 pi R^2 Solve for R fromVolume; 1200 = 4/3 pi R^3 R = 6.58 A = 546
Tricky. You need to flatten out the surface to work it out. Depends on the shape - if it's like a hemisphere then you can use the properties of a sphere - volume = 4/3 Pi R3 and surface area = 4 Pi R2 so if your dome is like half a sphere then its surface area = 2 Pi R2 and you can measure the radius R so can work it out!
to find the volume of a sphere the equation is v= 4 over 3 x pie x the radius cubed
Yes. Second contribution: Surface area of sphere = XXXVI = 36 square inches. When all the working out is done, which the previous contributor has failed to do, the answer is: Volume of the sphere = 20.311 cubic inches correct to three decimal places. This was achieved by rearranging the formula (4*pi*r2) for finding the surface area of the sphere in order to find its radius. The radius was then used in the formula (4/3*pi*r3) for finding the volume of the sphere.
To work out the area of a sphere, you have to know its radius. Once you know that: -- 'square' the radius (multiply radius times radius) -- multiply that result by 12.5664 The result is near the area of the sphere.
Formula for surface of sphere is 4 X pi X radius squared.4 x 4squared = 64 pie = 201.0622498so your answer is64 pie or 201.0622498(Either would work)
You work both out from measurements of the shape and the relevant formulae.
To calculate the surface area of a rectangular shape, you need to know the length and width of the rectangle. The formula for the surface area is given by multiplying the length by the width (Surface Area = Length × Width). If you're calculating the surface area of a rectangular prism, you would sum the areas of all six faces, which can be calculated using the formula: Surface Area = 2(length × width + length × height + width × height).
To work out the area of a composite shape, you will have to divide it into smaller figures.
Archimedes' discovery of the volume and surface area of a sphere laid foundational principles in geometry and calculus, influencing future mathematical research and applications. His formulas, which state that the volume of a sphere is two-thirds that of the cylinder surrounding it and that the surface area is proportional to the square of its radius, are crucial in fields such as physics, engineering, and astronomy. This work not only advanced mathematical understanding but also demonstrated the power of geometric reasoning and the concept of limits, which are essential in calculus. Archimedes' contributions continue to be relevant in various scientific and practical contexts today.
In a diffusion test, a sphere with a surface area to volume ratio of 2.1 m⁻¹ would demonstrate a more efficient diffusion process compared to solids with lower ratios. The higher ratio indicates that there is more surface area available for the substance to diffuse across relative to its volume, facilitating faster mass transfer. Consequently, we would expect the sphere to reach equilibrium more quickly than models with lower surface area to volume ratios. Overall, the efficiency of diffusion in the sphere would be enhanced due to its geometric properties.
It would help if the question was less obscure. What do you mean by "work"? How the surface area affects chemical processes (for example the surface area of catalysts), or diffusion, or surface areas and friction?
Approximately 546.1 ft2. To show work, The volume is 4/3 piR^3 and surface area is 4 pi R^2 Solve for R fromVolume; 1200 = 4/3 pi R^3 R = 6.58 A = 546