Wiki User
∙ 13y agolet x = small number and y = large number
25 % = 25/100 = .25
.25Y= X
Y = X+ 12
substitute and
Y = .25Y + 12
.75Y = 12
Y = 12/.75 = 16
X = .25Y = 4
Wiki User
∙ 13y agoMultiply the two smaller numbers and see if they equal the larger number.
Before that instruction, the problem gave you two numbers, and one numberis SMALLER than the other one.Now, the problem wants you to take the smaller one, figure out what 3 times itis, and then either increase that by 90 or multiply that by 90.
2 because 22+42 = 20
Yes. Thousandth is 10 times smaller.A thousandth is 10 percent of a hundredth. That's smaller.
Let the numbers be represented by a and b with a < b. Then a = b.25/100 and b = a + 12 As a = b.25/100 then 100a = 25b : 4a = b As b = a + 12 then substituting for b gives, 4a = a + 12 : 3a = 12 : a = 4. If a = 4 then b = a + 12 = 4 + 12 = 16 The two numbers are 4 and 12.
Multiply the two smaller numbers and see if they equal the larger number.
"smaller" is a binary operator: you need two numbers, 9 and another one, before you can decide whether 9 is smaller, the same or larger.
In that case, the smaller number is a factor of the larger one. The larger one is a multiple of the smaller one.
Before that instruction, the problem gave you two numbers, and one numberis SMALLER than the other one.Now, the problem wants you to take the smaller one, figure out what 3 times itis, and then either increase that by 90 or multiply that by 90.
If one number is divisible by another (in this case, 15 is divisible by 5), then the least common multiple is equal to the larger of the numbers (15), and the greatest common factor is equal to the smaller of the numbers (5).If one number is divisible by another (in this case, 15 is divisible by 5), then the least common multiple is equal to the larger of the numbers (15), and the greatest common factor is equal to the smaller of the numbers (5).If one number is divisible by another (in this case, 15 is divisible by 5), then the least common multiple is equal to the larger of the numbers (15), and the greatest common factor is equal to the smaller of the numbers (5).If one number is divisible by another (in this case, 15 is divisible by 5), then the least common multiple is equal to the larger of the numbers (15), and the greatest common factor is equal to the smaller of the numbers (5).
71/100 You can make it smaller, but it won't get you whole numbers so this is the best way in my opinion.
The GCF of the numbers is the greatest common factor no matter what their relationship is. When one number is a multiple of another number, the GCF is the smaller number.
Given any two distinct positive numbers, the percent increase of the larger l over the smaller s is 100[(l - s)/s. In this instance, the answer is 25 %.
11.11 % is ( 11.12 % ) smaller than 12.5 %.
Solve, or to work the problem until there are no other or smaller possible answers.
divide the smaller number by the larger number, and multiply by 100. 60 is 75% of 80.
Let n denote the smaller of the required numbers. Then, from the statement of the problem, 5 + 2n + n =29. Grouping like terms and transposing yields 3n = 29 - 5 = 24, or n = 8; the larger number is 5 + 2(8) = 21.