The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
There is no point in giving the volume as 1.1 - without any units. Is it meant to be 1.1 cm3 or 1.1 litres or 1.1 gallons or what? Because I know the answer, I can work out that if it is a solid object (hot hollow), the volume must be 1.1 cm3 and then the density is 9.8/1.1 gm per cm3 = 8.91 gm per cm3.
density = mass ÷ volume= 20 g ÷ 12 cm3≈ 1.67 g/cm3
density = mass ÷ volume = 30 g ÷ 10 cm3 = 3 g/cm3
The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3
speed m/s, volume L, ml or cm3, force newtons, work joules.
The volume is already stated. 75 cm3
69300 cm3 divided by 1163 cm3 = 59.587. 59 books.
There is no point in giving the volume as 1.1 - without any units. Is it meant to be 1.1 cm3 or 1.1 litres or 1.1 gallons or what? Because I know the answer, I can work out that if it is a solid object (hot hollow), the volume must be 1.1 cm3 and then the density is 9.8/1.1 gm per cm3 = 8.91 gm per cm3.
The density of the substance can be calculated by dividing the mass (31 g) by the volume (68 cm3). So, density = mass/volume = 31 g / 68 cm3 ≈ 0.46 g/cm3.
None. Cubic cm3 is a measure of "volume" in 9-dimensional hyperspace whereas cm3 is a measure of volume in the normal 3-dimensional space which we inhabit.
To find the density, divide the mass (53.5 g) by the volume (89.1 cm3). Density = mass / volume Density = 53.5 g / 89.1 cm3 = 0.601 g/cm3
density = mass ÷ volume= 20 g ÷ 12 cm3≈ 1.67 g/cm3
An object with a mass of 579 g and volume of 30 cm3 will have a density of 19.3 g/cm3.
cm3