Let y = x3 - 8, then y' = 3x2 + 0 = 3x2.
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
each individual part separated by addition or subtraction. ex: 3x2 + 5x + 7 has 3 terms, 3x2 and 5x and 7
Well 3x2 is 6 and 6 to the 2nd power is 36 and if you subtract one it is 35. you would write like this (3x2)x6-1
3x2= 6 6-(4x-2)= 6--8= 6+8 = 14 14+7 = 21
Let y = x3 - 8, then y' = 3x2 + 0 = 3x2.
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
each individual part separated by addition or subtraction. ex: 3x2 + 5x + 7 has 3 terms, 3x2 and 5x and 7
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
3x2 + 30x + 48 is a quadratic polynomial. If 3x2 + 30x + 48 = 0, then: 3(x + 2)(x + 8) = 0 ⇒ x + 2 = 0 → x = -2 or x + 8 = 0 → x = -8
y2-3x2+6x+6y= 18 is in standard form. The vertex form would be (y+3)2/24 - (x-1)2/8 = 1
3x2+26x+16 When factorised: (3x+2)(x+8)
Well 3x2 is 6 and 6 to the 2nd power is 36 and if you subtract one it is 35. you would write like this (3x2)x6-1
3x2= 6 6-(4x-2)= 6--8= 6+8 = 14 14+7 = 21