To write a Java program to check if a number is a twisted prime or not, you first need to create a function that checks if the number is prime. You can do this by iterating from 2 to the square root of the number and checking if the number is divisible by any of these values. Once you have verified that the number is prime, you can then check if the number remains prime after twisting its digits (reversing the number and checking if the reversed number is also prime). If both conditions are met, then the number is a twisted prime.
A prime number can only be divided by itself and 1
Find a prime number, add 2 to the number. Check if the new number is prime. IE : 3 is prime. 3+2 =5. 5 is prime. (3,5) are twin primes.
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Oh, what a lovely request! In FoxPro, you can create a program to print all prime numbers from 1 to 100 by using a loop to check each number for divisibility only by 1 and itself. If it meets this criteria, you can print it out on the screen. Remember, every number is unique and special, just like a happy little tree in a vast forest.
#include<stdio.h> main() { int check, i, x,y,m; printf("enter the number upto which check"); scanf("%d",&check); y=1; for(m=2; m<=check; m++) { for(x=2;x<m; x++) { y=m%x; if(y==0) break; } if(y!=0) printf("%d is prime number\n",m); else printf("%d is not a prime number\n",m); } getch(); }
No, it is not. You can check on prime-numbers.org
First write a program to generate the prime number. After one prime number was generated, divide the big int number by the prime number. If the remainder is zero then quotient is the second prime number ( also it is important to check whether the quotient is prime number or not because sometimes you will get wrong answer). Repeat the process until you get the result.
No its not a prime number Check out related links
#include<iostream.h> #include<conio.h> int main() { int i,n; clrscr(); cout<<"PROGRAM TO CHECK IF THE NUMBER IS PRIME OR NOT:"<<endl; cout<<"Enter a number:"; cin>>n; for(int i=2;i<n;i++) { if(n%i==0) cout<<"\nTHE NUMBER IS COMPOSITE"<<endl; else cout<<"\nTHE NUMBER IS PRIME"<<endl; } return 0; }
A prime number can only be divided by itself and 1
Use Wolfram|Alpha... go to the related link below, Wolfram|Alpha, and type in (is __ (number) prime) and then the program will compute that and tell you if it is prime or composite.
Find a prime number, add 2 to the number. Check if the new number is prime. IE : 3 is prime. 3+2 =5. 5 is prime. (3,5) are twin primes.
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the largest prime number under 100 is 97
Oh, what a lovely request! In FoxPro, you can create a program to print all prime numbers from 1 to 100 by using a loop to check each number for divisibility only by 1 and itself. If it meets this criteria, you can print it out on the screen. Remember, every number is unique and special, just like a happy little tree in a vast forest.
#include<stdio.h> main() { int check, i, x,y,m; printf("enter the number upto which check"); scanf("%d",&check); y=1; for(m=2; m<=check; m++) { for(x=2;x<m; x++) { y=m%x; if(y==0) break; } if(y!=0) printf("%d is prime number\n",m); else printf("%d is not a prime number\n",m); } getch(); }
#include<iostream.h> #include<conio.h> void prime(int n) { clrscr(); int num; cout<<"enter the numbers"<<endl; cin>>num; prime(num); getch(); } void prime(int n) { int prime=1,i; for(i=2;i<=n/2;i++) if(n%i==1) prime=0; if(prime==1) cout<<"the number"<<n>>"is prime"; else cout<<"the number"<<n<<"is not prime"; }