Q: How do you write a program in C plus plus plus plus How do you write a program in C to swap two variables without using the third oneo swap two variables without using the third one?

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3.75 - without using a calculator !

320...without using a calculator !

The ampersand causes two variables to share (point to) the same address in memory. For example: <php $first = "first"; $second = &$first; $second = "third"; echo "$first-$second"; // third-third ?> See the related link for an official, more detailed expanation.

An expression written with 1 or more variables is called an equasion

You first have to get rid of the numbers that don't have variables. then you divide by the variable and solve for it.

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a=a^b; b=a^b; a=a^b;

Use list assignment i.e. for two variables $a, $b: ($a,$b) = ($b,$a)

Without using a third party cheating program, unfortunetly, is impossible.

Global Variables Or: variables with names longer than 128 characters.

global

It is very easy. The program begins here..... /*Program to sum and print numbers without creating variables*/ #include<stdio.h> main() { clrscr(); printf("%d+%d=%d",5,2,5+2); getch(); } /*Program ends here*/ Now just by changing the numbers in the "printf" statement we can add, subtract, multiply and divide the numbers without using variables. Hence the problem is solved..........

Consider the following declarations:int x = 0;int y = 1;In order to swap the values, we need to use a temporary variable:int t = x;x = y;y = t;However, it is possible to swap the values without using a third variable:x ^= y ^= x ^= y;

int a = 5; int b = 10; a = a + b; // a = 5 + 10 = 15 b = a - b; // b = 15 - 10 = 5 a = a - b; // a = 15 - 5 = 10

Yes. int a, b; a= 2; b= 3; a= a+b;

#include <stdio.h> int main (void) { char *first= "Hello"; int second = 12; printf ("first=%s, second=%d\n", first, second); return 0; }

A = A xor B B = A xor B A = A xor B in C... A^=B; B^=A; A^=B;

By using a third temporary variable. $tmp = $a; $a = $b; $b = $tmp;