It already is in the form a+ib. a = root 7, the b=1 (i.e 1 x i ).
in decimal form the answer is 18.7082869
square root of 27 plus the square root of 75
plus or minus 6
That is the only way to write it exactly.
#include<iostream> int main() { unsigned num = 25; // or use user-input to assign the value unsigned root = sqrt ((double) num) std::cout << "The square root of " << num << " is " << root; }
in decimal form the answer is 18.7082869
The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8
45+45+90
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
square root of 27 plus the square root of 75
The square root of 27 plus the square root of 5 = 7.4322204
plus or minus 6
K0.5
That is the only way to write it exactly.
square root of 4x is 2 times square root of x, so answer is square root of x times 3 since it is 2 square roots of x plus one of them
#include<iostream> int main() { unsigned num = 25; // or use user-input to assign the value unsigned root = sqrt ((double) num) std::cout << "The square root of " << num << " is " << root; }
15.46482452