let x = number and y = difference
y = x -7
Let X = the different number the difference is x-7 the cube of the difference is (x-7) to the 3rd power (x-7)^3 - 4 = y
To write 7 as an ordinal number, you would write it as "seventh."
48-n=4n-7
X(the number) - 7- 5
x<7
X _ 7
Let X = the different number the difference is x-7 the cube of the difference is (x-7) to the 3rd power (x-7)^3 - 4 = y
1/4 ( x-7)
Your question is a bit confusing but i would say (7-x)3
To write 7 as an ordinal number, you would write it as "seventh."
48-n=4n-7
X = number 48 - X = 4X - 7
When you write the decimal number '7' in Base-2 (binary), you write '0111'.
Not necessarily. The difference between a = 7 & b = 7 is 0, and that is not a natural number.
7 - n
Seven.
X(the number) - 7- 5