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1125 = 3 x 3 x 5 x 5 x 5

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14y ago

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What is the prime factorization of 1125 in exponential form?

1125 = 32*53


Is 1125 a prime?

1125 is not a prime number because it has more than two factors


Is 1125 a prime or composite number?

composite


What are the prime factorization in both expanded and exponent form with these numbers 2500 1125 279 and 644?

12


What is the prime factorization of 1125?

1,125 = 3 x 3 x 5 x 5 x 5


Is 1125 a prime number?

No. Consider:1125 = 45 * 25 = 9 * 5 * 5 * 5 = 3 * 3 * 5 * 5 * 5A prime number is defined as an integer that has no factors, so 1125 does not meet that qualification. It is instead a composite number.


What are the prime factors factors of 1125?

The prime factors of 1125 are: 3, 5


What are the factors and prime factors of 1125?

1125 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 12 factors of 1125 are 1, 3, 5, 9, 15, 25, 45, 75, 125, 225, 375, and 1125.The proper factors of 1125 are 1, 3, 5, 9, 15, 25, 45, 75, 125, 225, and 375 or,if the definition you are using excludes 1, they are 3, 5, 9, 15, 25, 45, 75, 125, 225, and 375.The prime factors of 1125 are 3, 3, 5, 5, and 5. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 2 distinct prime factors (listing each prime factor only once) of 1125 are 3 and 5.The prime factorization of 1125 is 3 x 3 x 5 x 5 x 5 or, in index form (in other words, using exponents), 32 x 53.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.3 x 3 x 5 x 5 x 5


What is number do you multiply to get 1125?

1 and 1125.


What is 1125 expressed as the product of prime factors?

1125 = 3 * 3 * 5 * 5 * 5


What is 1125 in decimal form?

1125 in decimal form is simply 1125. Decimal form is the standard number system we use in everyday life, which is based on powers of 10. In this case, 1125 is already in decimal form as it is written in base 10.


How do you prime factorize the sum 9000?

9000 is an even number, it ends in '2'. Since '2' is a prime number , divide by ;2; Hence 9000 / 2 = 4500 Divide by '2' again and continue 4500/2 = 2250 2250/2 = 1125 Since '1125' ends in '5' it will divide by '5' , a prime number. 1125/5 = 225 225/5 = 45 45/5 = 9 9 /3 = 3 3/3 = 1 So the prime factors are 2,3,& 5. Fully 2^(3) X 5^(3) X 3^(2) = 9000