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To convert the number ( (6 , 13)_7 ) into standard form, first note that it is in base 7. The number can be expressed as ( 6 \times 7^1 + 13 \times 7^0 ). Since ( 13 ) is not a valid digit in base 7 (valid digits are 0-6), it seems there might be a misunderstanding. If you meant ( (6 , 1 , 3)_7 ), then it would equal ( 6 \times 7^2 + 1 \times 7^1 + 3 \times 7^0 = 6 \times 49 + 1 \times 7 + 3 = 294 + 7 + 3 = 304 ) in decimal (standard) form.

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AnswerBot

2w ago

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