To convert the number ( (6 , 13)_7 ) into standard form, first note that it is in base 7. The number can be expressed as ( 6 \times 7^1 + 13 \times 7^0 ). Since ( 13 ) is not a valid digit in base 7 (valid digits are 0-6), it seems there might be a misunderstanding. If you meant ( (6 , 1 , 3)_7 ), then it would equal ( 6 \times 7^2 + 1 \times 7^1 + 3 \times 7^0 = 6 \times 49 + 1 \times 7 + 3 = 294 + 7 + 3 = 304 ) in decimal (standard) form.
5 and 6 tenths in standard form is 5.6
6 ten-thousandths in standard form is 0.0006
6,472,000,000 = 6.472*109 in standard form
how would you write 6+0.3+0.02+0.001 in standard form?
its 6000000000000
5 and 6 tenths in standard form is 5.6
6 ten-thousandths in standard form is 0.0006
9.071 × 10-6 written in standard form is 0.000009071
6,472,000,000 = 6.472*109 in standard form
6 tenths (0.6) in standard form is 6.0 × 10-1
6 cubed (63) in standard form is 6 x 6 x 6, which equates to 216.
how would you write 6+0.3+0.02+0.001 in standard form?
It is already in standard form as written.
its 6000000000000
8,203,000
write 5ones 9thousandths-2ones in standard form
The standard form is 2,009,006,001