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Q: How do you you convert 3V p-p to Vdc?
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"dc" is a constant voltage without any variation. So the 'vpeak' of 60 Vdc is 60 V.


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How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?

Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.


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