8 = 4*2
So 5*8 = 5*(4*2) which, by the associative property, = (5*4)*2
= 20*2
Can you do 20*2 more easily than 5*8?
If not, you need another round of associate property.
20 = 10*2
So 20*2 = (10*2)*2 = 10*(2*2) = 10*4
And if you cannot do 10*4 then this question is beyond you anyway and knowing 5*4 is not going to help.
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2X10 would work, as would 5X4.
no. 6x8 =48. 5x4 + 1x4 =20 + 4 =24.
20
5x4 - 2x = x*(5x3 - 2) and that cannot be factorised further without invoking surds.
the product of 5x4 because 5x4=20 and 5+4=9