When an atomic nucleus splits into two or more pieces, the masses of
the pieces doesn't add up to the mass of the original nucleus. There's
always some mass missing, and some energy is always radiated from
the process.
How much energy ? Exactly what you get when you multiply
(the amount of mass that's missing) times ( c2 ) .
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Work gives us energy in Joules, which can be subbed back into the first equation to solve for power.
The sun produces energy by the fusion of nuclei of small elements into those of larger elements: for example hydrogen into oxygen. This process involves a loss of mass and that mass is converted into solar energy - in line with Einstein's equation.
This just means to list values of x and then plug them into the equation to find the value of y for that x. so in (x,y) form:(1,8) (2,16) (3,24) and so on.
They fit the equation t = 0 exactly.
When a single heavy nucleus splits into two or more lighter nuclei (fission), the sum of their masses is less than the mass of the original nucleus. Some mass is missing, and some energy is released. When two light nuclei fuse into a single heavier nucleus (fusion), the mass of the heavier one is less than the sum of the masses of the two light ones. Some mass is missing, and some energy is released. In both events, the missing mass has been converted to energy. If the amount of missing mass is 'm', and you multiply 'm' by the square of the speed of light 'c2' , the answer you get is the amount of energy that was released 'e'. e = mc2