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the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is :

s = s0+vt + 1/2at^2

s0 = initial displacement (you can equate to 0, if you start at 0)

vt = starting velocity times time (you can equate to 0 if initial velocity is 0)

s= final displacement

so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")

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Related Questions

How does the total distance changes as the total time increases in case of uniformly motio?

For uniform motion, distance = velocity*time where uniform implies that the velocity is a constant. Therefore distance = v*time and so, if time increases by t, the distance increases by vt.


Accelerated motion is repersented by a what line on a distance time graph?

Accelerated motion is represented by a curved line on a distance-time graph. This curvature indicates that the distance covered changes at a varying rate over time, reflecting the object's acceleration. If the object is accelerating uniformly, the curve will be a parabola. In contrast, a straight line indicates constant velocity, where the distance changes at a steady rate.


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