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the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is :

s = s0+vt + 1/2at^2

s0 = initial displacement (you can equate to 0, if you start at 0)

vt = starting velocity times time (you can equate to 0 if initial velocity is 0)

s= final displacement

so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")

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Q: How does the total time changes as the total distance increases in case of uniformly accelerated motio n?
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