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depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.

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12y ago

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An 8-kg mass is in free fall. what is the velocity of the mass after 9 seconds?

An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.


If a rock falls from a cliff for 9 seconds how fast is it going when it reaches the bottom?

Assuming that no net external forces are taking place, such as friction or air resistant, the only force acting upon the falling rock would be gravity. Using one of the kinematic equations, we can solve for the final velocity of the rock: v(final) = v(initial) + at We can substitute 0 for "v(initial)" since the rock is starting from rest. We can also substitute 9.81 meters per second squared for "a", which is the gravitational acceleration on Earth. Finally, we can substitute 9 seconds for "t". This gives us: v(final) = 0 + (9.81)(9) v(final) = 88.29 meters per second.


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