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The train has traveled along the track for 18 meters.

Multiplying and adding, the distance traveled is:

(1 x 20)m - (0.5 x 4)m

= 20 - 2

= 18

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Q: How far is the train located from its start after completing both movements if it goes forward at a speed of 1 ms for 20 seconds then stops and goes backward at a speed of 0.5 ms for 4 seconds?
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