Solve be substitution... m+n=1000 0.05m+0.06n=57 Take one of the equation and find "m" m=1000-n substitute into the other equation 0.05(1000-n)+0.06n=57 50-0.05n+0.06n=57 50-0.01n=57 -0.01n=-7 n=700 Now you have found "n" now find "m" m=1000-n m=1000-700 m=300 m=300 and n=700
There are 1000 of them.
15 kN = 15 x 1000 N = 15000 N
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
Sum of first n numbers = n/2(n +1) = 500 x 1001 = 500500
1000n = 0.6 Therefore, 0.6/1000 = n Therefore, n = 0.0006
about 1000 tons
The Hot n' Heavy was created on 2009-06-02.
Hard 'n' Heavy was created on 1981-05-25.
1000 times as heavy.
To get a list of the squares of the first 1000 numbers we can do:> [n^2 | n sum [n^2 | n
453.59237
1 metric tonne is 1000 kilograms. Is that heavy?
N = .0006
1000 kg
About 1000 lbs.
1000