10.'384615' (recurring decimals) feet
17.45 feet.
15 feet high
To determine the height of the tree based on the shadow length, we can use the concept of similar triangles. If the tree casts a shadow of 1 foot while a 1-foot pole also casts a shadow of 1 foot, then the height of the tree is the same as the height of the pole. Thus, the tree is also 1 foot tall.
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
Divisibles, the 6 foot man would cast a shadow 2 feet long.
27.3 feet
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
17.45 feet.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
15 feet high
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
It works out as 12 feet and 4 inches in height
3.4
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
Not enough information has been given to solve this problem such as: What is the angle of elevation?
Divisibles, the 6 foot man would cast a shadow 2 feet long.
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?