Q: How high is a tree that casts a 27 foot shadow at the same time a 5 foot man cast a 13 foot shadow?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

17.45 feet.

15 feet high

5.5/8 = x/20 x=5.5*20/8 = 13.75 feet

Divisibles, the 6 foot man would cast a shadow 2 feet long.

40 ft

Related questions

27.3 feet

If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.

17.45 feet.

To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.

15 feet high

The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.

It works out as 12 feet and 4 inches in height

3.4

5.5/8 = x/20 x=5.5*20/8 = 13.75 feet

Not enough information has been given to solve this problem such as: What is the angle of elevation?

Divisibles, the 6 foot man would cast a shadow 2 feet long.

1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?