The bottom of the ladder is 14 feet from the house and the ladder is an 18 foot ladder that reaches to the top of the house. The question is how tall is the wall of the house? I reworded it to show some assumptions I made about what you are asking.
If these are not true, let me know
So the ladder, the wall of the house and the distance from the ground to the house form a right triangle with hypotenuse 18 and base 14.
Now, 142 +x2 =182
where x is the height of the wall.
Solving for x we find x=(Square root (324-196)=Square root 228
since 228 is 4x57 the answer is
2(square root (57)
57 is 3 x19 so it won't help to simplify it more.
Use Pythagoras' theorem: 122-32 = 135 and its square root gives the answer of 11.619 feet rounded to 3 decimal places
I guess you mean: how high is a 14 foot high pile of trash in inches? 1 ft = 12 in ⇒ 14 ft = 14 x 12 = 168 in The 14 foot high pile of trash is 168 inches high.
14 studs
2 Kings 18:27 ... piss, no pisses 1 Kings# Behold, I will bring evil upon the house of Jeroboam, and will cut off from Jeroboam him that pisseth against the wall.--14:10 # He slew all the house of Baasha: he left him not one that pisseth against a wall ... according to the word of the LORD.--16:11-12 # Behold, I will bring evil upon thee, and will take away thy posterity, and will cut off from Ahab him that pisseth against the wall--21:21 == # For the whole house of Ahab shall perish: and I will cut off from Ahab him that pisseth against the wall--9:8 # Hath he not sent me to the men which sit on the wall, that they may eat their own dung, and drink their own piss with you?--18:27
Is this a trick question? You only need three figures if you are calculating cubic feet. You have just described a "Box" not a backsplash (normally figured in linear feet).
14
Use Pythagoras' theorem: 122-32 = 135 and its square root gives the answer of 11.619 feet rounded to 3 decimal places
98
The ladder's weight does not affect the friction force between the ladder and the wall. The friction force is the horizontal component of the normal force acting on the ladder, which is equal to mass * gravity * cosine(angle). In this case, it would be (80 kg + 20 kg) * 9.81 m/s^2 * cos(60 degrees).
You Can't Trust a Ladder was created on 2005-06-14.
14
14 feet
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A. 11 feet B. 13 C. 12 D. 14.
14 Min.
there are 12 studs and 11 spaces in a 14' wall
7 on one side and 14 on both sides