Any product of any list of factors is zero, if one of the factors is zero.
0 plus 0 plus 0, repeated multiple times, equals 0. Adding zero to zero does not change the value, so regardless of how many times you add it, the sum remains 0. Therefore, the final result is simply 0.
0.04c + 1.6 = 00.04c = -1.6c = -40
50 - 40 = 10 + 0
-4
To divide 41 into 1353, you perform the division operation ( 1353 ÷ 41 ). This calculation gives you 33 with a remainder of 0, meaning 41 fits into 1353 a total of 33 times exactly. Therefore, ( 1353 = 41 \times 33 ).
The solution to 40 plus 40 times 0 plus 1 is 41. The number name is forty-one.
Order or operations: 40 + 40 x 0 + 1 = 40 + 0 + 1 = 41
40 + 40 x 0 + 1 The answer to this would be 41. In reference to BIMDAS, multiplication is always calculated before addition. The multiplication involves 40 x 0....which is 0 Thus...40 + 0 + 1 = 41
40 + (40 x 0) + 1 = 41.
If you mean: 40+(40*0)+1 = 41
0. Any equation that has times 0 equals 0.
100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37
0.04c + 1.6 = 00.04c = -1.6c = -40
Interesting. Assuming "times" is a variable: You're question is what is 0/times + times * (0/+0*100) That would be 0 + times * (0/0) 0/0 = infinity(Anything over 0 = infinity) So then, you can figure out that it is times * infinity which is infinity.
50 - 40 = 10 + 0
In 2005, Julio Santana played in 41 games, all for the Milwaukee Brewers, and batting in 40 of them. He had 1 at bat, getting 0 hits, for a .000 batting average, with 0 runs batted in. He was walked 0 times. He struck out 0 times.
In the absence of any brackets, that equals 12.