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This is my own way of finding a binary of a number. We all know that binary is in base 2 (it only have 2 values - 0 and 1). Here is how I do it:

Steps:

1) Divide the number by 2. If there is a remainder, then write the number 1 as the first binary number otherwise write 0.

Ex:

7/2 = 3.5 ---> Since there's a remainder write 1.

8/2 = 4 ---> If there's no remainder write 0.

2) Repeat the first step using the value that was derived on the first one. Continue doing so until the number is not less than 1

Ex:

3/2 = 1.5 ---> Our binary now is 11.

4/2 = 2 ---> Our binary here is 00.

Repeat:

1/2 = 0.5 ---> Since the number is less than zero, just write the final result. Our binary now is 111.

2/2 = 1 ---> Again here we write 000.

1/2 = 0.5 ---> Now we write it as 0001.

3) After getting the final value, reverse your answer and it will now be the binary form.

Answer:

710 = 1112

810 = 10002

Note: Please edit my answer if you are a bit confuse with the steps.

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