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Log the times for each employee. Calculate the number of minutes. Add them together. Divide by the number of employees. If there are a lot of employees you could take a sample but in that case you may wish to consider stratification by job category.
A four log kill is where a disinfectant (or process) is able to kill 10e4 (10,000) organisms of a test inoculum. A four log kill can also be expressed as killing 99.99% of organisms. In many cases, a four log kill is considered the minimum level of high level disinfection, with a six log kill being required for higher threat agents such as anthrax, etc.
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
how do i log in
log(5)125 = log(5) 5^(3) = 3log(5) 5 = 3 (1) = 3 Remember for any log base if the coefficient is the same as the base then the answer is '1' Hence log(10)10 = 1 log(a) a = 1 et.seq., You can convert the log base '5' , to log base '10' for ease of the calculator. Log(5)125 = log(10)125/log(10)5 Hence log(5)125 = log(10) 5^(3) / log(10)5 => log(5)125 = 3log(10)5 / log(10)5 Cancel down by 'log(10)5'. Hence log(5)125 = 3 NB one of the factors of 'log' is log(a) a^(n) The index number of 'n' can be moved to be a coefficient of the 'log'. Hence log(a) a^(n) = n*log(a)a Hope that helps!!!!!