The amount of water displaced by the block is the volume of the block.
so (volume of water with block in it)-(original volume of water)= volume of block
Using the rough rule-of-thumb: 1 liter of water = 1 kg.-- The block sinks until it has displaced 720 liters of water. At that point,the mass of the displaced water has the same weight as the mass of theblock has, and the block sinks no further.-- The block still has 280 liters of its volume above water. If that were submerged,another 280 kg of water would be displaced.-- The additional 280 kg of water would weigh (280 x 9.8) = 2,744 newtons (617.3 pounds).That much additional buoyant force would fight the effort to submerge the block.It takes an additional 2,744 newtons (617.3 pounds) to keep the block under water.
It depends on the block! Not all blocks are the same shape nor volume.
It is the mass of the block divided by its volume.
If its a cuboid, volume = length * breadth * height .
The piece of wood will float (partially submerged) in water. Filling up a displacement can with water and letting the water drain at the sprout is the starting point. When the water stops draining, place a dry (empty) measuring cylinder to collect water coming out of the sprout from here on. Gently lower the wood block on the water. It floats. Gently push the block down until it is just submerged. The volume in the displacement can is the volume of the wood block. The tricky part is how to push the block down without agitating the water, making the reading inaccurate. One possibility is to have a box of known weights around. Carefully place standards on the block without the weights toppling over -- starting with a heavier standard and proceeding to lighter standards (available down to 1 mg). If the standard makes the block submerge below the top surface, start over. Some volume uncertainty will remain for one run. Repeating the exercise and averaging the data will lower the uncertainty. If the piece of wood is irregular -- not a regular shape, we can try the following. find a weight that will let the block submerge completely in water with a string. Measure the volume of water displaced. Then do the weight and string without the piece of wood and measure the volume of water displaced. The difference in volume is the answer for the piece of wood. Again, repeating the experiment reduces the measurement error.
The volume of water is the same.
The metal block will displace a volume of water equal to its own volume. By measuring the volume of water displaced, you can then determine the mass of the metal block - as long as you know the density of water (1 gram per cubic centimeter).
-- The aggregate density of the wood block is 700/1000 = 0.7 the density of water. -- So, as soon as the wood has displaced 0.7 of its volume in water, it has displaced its entire weight in water, and floats. -- The wood floats with 0.7 of its volume below the surface and 0.3 of its volume above it.
The water level will rise to a lesser height, Δh2, because the smaller block displaces less water due to its smaller volume, even though it has the same weight as the larger block. This is because an object floats when the weight of the water displaced is equal to the weight of the object itself.
A graduated cylinder or volumetric flask could be used to measure the displacement of water when the wood block is submerged in it. By measuring the volume of water displaced, you can determine the volume of the wood block. A balance can then be used to measure the mass of the wood block, allowing you to calculate its density.
Butcher block counters are cheaper than granite, however not by much. Butcher block ranges from $40-$65 per square foot and granite is around $40-$100 per square foot.
The matter of the block displaced the water causing the water to rise
Using the rough rule-of-thumb: 1 liter of water = 1 kg.-- The block sinks until it has displaced 720 liters of water. At that point,the mass of the displaced water has the same weight as the mass of theblock has, and the block sinks no further.-- The block still has 280 liters of its volume above water. If that were submerged,another 280 kg of water would be displaced.-- The additional 280 kg of water would weigh (280 x 9.8) = 2,744 newtons (617.3 pounds).That much additional buoyant force would fight the effort to submerge the block.It takes an additional 2,744 newtons (617.3 pounds) to keep the block under water.
Block being a box: Height * Length * Depth = Volume Giving the three dimensions available.
The buoyant force on both blocks would be equal because it depends on the volume of the object displaced in the water, not the material it's made of. Both blocks would displace the same volume of water, experiencing the same buoyant force.
Yes, this is essentially true. Well over 99.9% of the mass of any atom is in the nucleus. The electrons in their orbitals around that nucleus actually determine the spacial volume that the atom occupies. And on an atomic scale, the distance from the nucleus to the outer boundaries of the electron cloud is enormous. The atom is mostly empty space, and, therefore, anything made up of atoms is mostly empty space.
Capstone