How long does it take to fall 9.6 meters?

Answer 1

Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:

d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.

If V0= 0 and a = 9.8 m/s2, then: 9.6 m = (4.9 m/s2)*t2

t2 = (9.6 m) / (4.9 m/s2) = 1.9592 s2 ; t = sqrt(1.9592 s2) = 1.3997 seconds