Wiki User
∙ 10y agoThe diagonal is about 16.97 inches long.
Wiki User
∙ 10y agoEach of them is 14.14 inches long. (rounded)
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
To find the diagonal, use the Pythagorean theorem by drawing a diagonal through the square. You then have two sides that should equal the hypotenuse ( or diagonal). The equation should look like 8^2 + 8^2 = h^2. or 64+64= h. 128=h take the square root of 128 and you have your answer. the answer should be around 11.
The diagonal is 221.2 inches long.
Each of them is 14.14 inches long. (rounded)
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
If a square has an area of 86 square inches, each side is about 9.273 inches long.
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
26.4 inches for the diagonal.
6 inches on each side. To get square inches of a square you multiply length by width. So, 6 inches by 6 inches = 36 square inches.
To find the diagonal, use the Pythagorean theorem by drawing a diagonal through the square. You then have two sides that should equal the hypotenuse ( or diagonal). The equation should look like 8^2 + 8^2 = h^2. or 64+64= h. 128=h take the square root of 128 and you have your answer. the answer should be around 11.
The diagonal is 221.2 inches long.
6 inches.
Each side is six inches long.
Each side is 9 inches long