The diagonal is about 16.97 inches long.
Each of them is 14.14 inches long. (rounded)
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
The diagonal is 221.2 inches long.
To find the diagonal, use the Pythagorean theorem by drawing a diagonal through the square. You then have two sides that should equal the hypotenuse ( or diagonal). The equation should look like 8^2 + 8^2 = h^2. or 64+64= h. 128=h take the square root of 128 and you have your answer. the answer should be around 11.
Each of them is 14.14 inches long. (rounded)
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
If a square has an area of 86 square inches, each side is about 9.273 inches long.
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
26.4 inches for the diagonal.
6 inches on each side. To get square inches of a square you multiply length by width. So, 6 inches by 6 inches = 36 square inches.
The diagonal is 221.2 inches long.
To find the diagonal, use the Pythagorean theorem by drawing a diagonal through the square. You then have two sides that should equal the hypotenuse ( or diagonal). The equation should look like 8^2 + 8^2 = h^2. or 64+64= h. 128=h take the square root of 128 and you have your answer. the answer should be around 11.
Each side is six inches long.
Each side is 9 inches long
6 inches