It have 4 axis of symmetry . Two Perpendiculars and two Diagonals
Rotational symmetry refers to symmetry of the figure when it is rotated about a single point in the same plane. Lines of symmetry apply to reflections. You do not have lines of rotational symmetry.
Because the circle's diameter has infinite lines of symmetry
A square
Yes, both triangles and squares have lines of symmetry and rotational symmetry. An equilateral triangle has three lines of symmetry and a rotational symmetry of order 3, meaning it can be rotated by 120 degrees and still look the same. A square has four lines of symmetry and a rotational symmetry of order 4, allowing it to be rotated by 90 degrees and still appear unchanged. Other types of triangles and quadrilaterals may have different numbers of symmetries based on their specific shapes.
Yes, the capital letter N has rotational symmetry but no lines of symmetry:
7
Rotational symmetry refers to symmetry of the figure when it is rotated about a single point in the same plane. Lines of symmetry apply to reflections. You do not have lines of rotational symmetry.
Because the circle's diameter has infinite lines of symmetry
A square
no shape does! * * * * * Not true. A parallelogram has rotational symmetry of order 2, but no lines of symmetry.
Rotational symmetry is based on points of rotation not lines
a square based pyrmaid has 24 lines of symitry
Yes, the capital letter N has rotational symmetry but no lines of symmetry:
First of all, your grammar is terrible. The question should be "Does a triangle have 2 lines of symmetry and 2 lines of rotational symmetry? and the answer is no. A triangle can not have 2 lines of rotational symmetry, because you only rotate the image, you do not use any lines.
Yes. A circle has infinitely many lines of symmetry and it also has rotational symmetry of infinite order.
Not necessarily, except rotational symmetry of order 1.
A matchbox is rectangular in shape. A rectangle has 2 lines of rotational symmetery. So, a matchbox has 2 lines of rotational symmetry.