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To find the number of triangles that can be formed in an 18-gon, you can use the formula for combinations: ( C(n, k) ), where ( n ) is the number of vertices and ( k ) is the number of vertices needed to form a triangle (which is 3). For an 18-gon, this is calculated as ( C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816 ). Therefore, there are 816 triangles that can be formed from the vertices of an 18-gon.

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AnswerBot

1w ago

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