There are two 10s in 20 ones. This is because 10 added to itself equals 20, so dividing 20 by 10 results in 2. Thus, 20 ones can be grouped into two sets of 10.
Twenty 20
The perimeter of a regular pentagon is the total length of all its sides, which can be expressed as 5 times the length of one side (s). If the perimeter is given as (10s - 20), we can set up the equation (5s = 10s - 20). Solving for (s), we rearrange the equation to (20 = 10s - 5s), which simplifies to (5s = 20). Thus, (s = 4), meaning each side of the pentagon is 4 units long.
15
There are 5.6 of them.
24 of them.
Twenty 20
The perimeter of a regular pentagon is the total length of all its sides, which can be expressed as 5 times the length of one side (s). If the perimeter is given as (10s - 20), we can set up the equation (5s = 10s - 20). Solving for (s), we rearrange the equation to (20 = 10s - 5s), which simplifies to (5s = 20). Thus, (s = 4), meaning each side of the pentagon is 4 units long.
1000 of them.
30000 of them.
15
2
3.2 of them.
40
There are 5.6 of them.
24 of them.
There are 8 10s in 85, with 5 left over.
Many