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How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is allowed?
Wiki User
∙ 13y ago
Reqd no. is 13-digits.. available digits are 1 2 3 4 5.. Numbers which are divisible by 4 can be determined by the last two digits.. from the given combinations,, the numbers div by 4 are 12, 24, 32, 44, 52
so.. the number's last two digits can be any of the above 5.
Hence, we have to calculate the combinations for the first 11 digits..
Ans: (5C1)^11 * 5
i.e 5^12
Wiki User
∙ 13y ago
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How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many combinations are there for the numbers 1-56 with 9 numbers?
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many combinations are there for the numbers 1-56 with 9 numbers?
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?
-4
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 3 digit numbers from 2571?
When the repetition is allowed: 4*4*4 = 64 numbers. Without repetition: 4*3*2 = 24 numbers.
How many 4 digit numbers can be made to give the sum of 6?
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
