Each 16 inch tile is 1.78 square feet. You would need 169 tiles, plus some for spoilage.
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Two tiles of 16 ft*16 ft will cover 512 square feet.
LXW= sq inches Sq Inches divided by 144 (sq inches in a sq foot)= the # of sq ft per tile (It will be about 1.7 but you have to do the math to be exact) 50 sq feet divided by (sq ft per tile) = the number of tiles somewhere between 25 -30 tiles...
500 sq ft = 500*12*12 = 500*144 = 72000 sq inches You would need 72000/256 tiles of 16*16 sq inch ie 281.25 tiles. The above answer is good only for mathematical purposes. In real life, you would need to take account of the shape of the area and also make an allowance for wastage.
Type your answer here... You first need to make an assumption that both the tiles are square and the ceiling is square, otherwise there are any number of possible answers. Each tile would therefore measure 2 ft x 2 ft. The ceiling would be 7 tiles x 7 tiles. The width of the ceiling would be 7 tiles x 2 feet = 14 feet.
13 x 13 (assumed inches) is 13/12 feet x 13/12 feet, so the area of one tile is 169/144 square feet. To cover 100 square feet you need (100)/(169/144) tiles which works out to (100 x 144)/169 = 14400/169 = 85.2, make it 86 tiles