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73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
The numbers from 1 to 39 include both single-digit and double-digit numbers. There are 9 single-digit numbers (1 to 9) and 30 double-digit numbers (10 to 39). Therefore, the total number of digits is 9 (from single-digit numbers) + 60 (from double-digit numbers, as each has 2 digits) = 69 digits in total.
There are only two smaller 3-digit numbers and both of them have repeated digits.
There are three such numbers: 12, 24 and 36.
Since both of those numbers contains four digits, there are no three-digit numbers between them.
73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
The numbers from 1 to 39 include both single-digit and double-digit numbers. There are 9 single-digit numbers (1 to 9) and 30 double-digit numbers (10 to 39). Therefore, the total number of digits is 9 (from single-digit numbers) + 60 (from double-digit numbers, as each has 2 digits) = 69 digits in total.
There are only two smaller 3-digit numbers and both of them have repeated digits.
There are three such numbers: 12, 24 and 36.
The two-digit numbers with both digits even are formed using the even digits 0, 2, 4, 6, and 8. However, since the first digit (the tens place) cannot be 0, the possible choices for the first digit are 2, 4, 6, and 8 (4 options). The second digit (the units place) can be 0, 2, 4, 6, or 8 (5 options). Therefore, the total number of two-digit numbers with both digits even is (4 \times 5 = 20).
To compare two whole numbers with different digits, you first look at the number of digits in each number. The number with more digits is larger since whole numbers increase in value with the addition of digits (for example, 100 is greater than 99). If both numbers have the same number of digits, you can compare them digit by digit from left to right to determine which is larger.
Six three-digit numbers contain only the digits 5 and 6. This is assuming you mean both the digits of 5 and 6. If not than 8, as it would include 555 and 666. 556, 565, 566, 655, 656, 665
There are 2000 possible five digit numbers that can be formed from the digits 02345 that are divisible by 2 or 5 or both. To be divisible by 2, the last digit must be even, namely 0, 2 or 4 (in the digits allowed). To be divisible by 5, the last digit must be 0 or 5. Thus to be divisible by 2 or 5 or both, the last digit must be 0, 2, 4 or 5 (a choice of 4). Presuming that a 5 digit number must be at least 10000, then: For the first digit there is a choice of 4 digits (2345); for each of these there is a choice of 5 digits (02345) for the second, making a total so far of 4 x 5 numbers; for each of these choices for the first and second digits there is a choice of 5 digits (02345) for the third digit making the total so far (4 x 5) x 5 numbers; for each of these choices for the first three digits there is a choice of 5 digits (02345) for the fourth digit making the total so far (4 x 5 x 5) x 5 numbers; for each of these choices for the first four digits there is a choice of 4 digits (0245 - as discussed above) for the last digit, giving a total of (4 x 5 x 5 x 5) x 4 numbers. So the total number of five digit numbers so formed is: number = 4 x 5 x 5 x 5 x 4 = 2000.
None. 1221 and 3443 are both 4-digit palindromes but no digit has remained the same between the two. First and fourth, second and third.
The presence of zeros in the product of multi-digit numbers with zeros and one-digit numbers depends on the specific digits involved in the multiplication. If the multi-digit number contains a zero, it can lead to zeros in the product, particularly if the zero is in a position that affects the final result. Conversely, if the one-digit number is non-zero and the multi-digit number has no zeros in significant positions, the product will not contain any zeros. Thus, the occurrence of zeros in the product is determined by the combination of digits in both numbers.