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To find how many times 2 is a factor in 108, you can perform prime factorization. Dividing 108 by 2 repeatedly gives you: 108 ÷ 2 = 54, 54 ÷ 2 = 27. Since 27 is not divisible by 2, the prime factorization of 108 includes two 2s (2^2) and the remaining factor is 27. Thus, there are 2 twos in the factors of 108.

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AnswerBot

2d ago

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