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To find the number of 3-digit combinations using the digits 0 to 9 with repetition allowed, we consider that each digit can be any of the 10 digits (0-9). Since there are 3 positions in the combination, the total number of combinations is calculated as (10 \times 10 \times 10), which equals 1,000. Therefore, there are 1,000 possible 3-digit combinations.

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2w ago

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Related Questions

How many 3 digit number are formed using the digits 3 5 7?

With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753


How many ways can you combine 2 digits?

To combine 2 digits, you can choose from the 10 digits available (0-9). If repetition is allowed, there are (10 \times 10 = 100) combinations. If repetition is not allowed, there are (10 \times 9 = 90) combinations, as you select the first digit and then choose a different second digit.


How combination in a 9 digit number?

There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 255 combinations in all.


How many different combinations can be created using the digits 0-9 is the first digit cannot be 0 and repetitions are not allowed?

8877690


What are all the ways to combine 123456789 in 7 digits without repeating?

To combine the digits 1 through 9 into 7-digit combinations without repeating any digits, you can select any 7 digits from the 9 available. The number of ways to choose 7 digits from 9 is given by the combination formula ( C(9, 7) ), which equals 36. Each selection of 7 digits can then be arranged in ( 7! ) (factorial) ways. Therefore, the total number of 7-digit combinations is ( 36 \times 7! = 36 \times 5040 = 181440 ).


How many 4 digit combanations using the numbers 1-7?

There are 840 4-digit combinations without repeating any digit in the combinations.


How man 7 digit combinations can be made using numbers 0 through 9?

10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.


How many 2 digit numbers can be formed using the digits 1 3 5 7 9 and 0 if repeating is not allowed?

There are 25 such numbers.


How many 5 digit combinations are there in six digits?

about 1,0000000000000


How many 4 digit combinations can be made from 6 digits?

Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.


How many number combinations for 9 digits repeat allowed?

Well honey, if you're talking about 9-digit numbers with repeating digits allowed, you've got 10 options for each digit (0-9), so that's 10 choices for each of the 9 digits. So, the total number of combinations would be 10^9, which is a whopping 1 billion possible combinations. Hope that clears things up for ya!


What nine-digit number is divisible by 11 and has no repeating digits?

987652431