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How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many 3 digit numbers can be formed with set 15678 if repetition is allowed?
There are 5*5*5 = 125 such numbers.
How many 2 digit odd numbers can be formed using the digits 123456789 without repitition?
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 4 digit numbers can be formed from the digits 123456789?
There are 3024 of them.
How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many 3 digit numbers can be formed with set 15678 if repetition is allowed?
There are 5*5*5 = 125 such numbers.
How many 2 digit odd numbers can be formed using the digits 123456789 without repitition?
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?
Six (6)
How many five digit multiples of 3 are formed using 012346 and 7 without repetition?
There are 600 such numbers.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
