To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
Infinitely many. Only 6 with both, the number of 8s and the number of 3s being positive.
102 ÷ 3 = 34
To find out how many times 12 can go into 140, you divide 140 by 12. This equals approximately 11.67. Therefore, 12 can go into 140 a total of 11 times, with a remainder.
15
32
37.6666667
Infinitely many. Only 6 with both, the number of 8s and the number of 3s being positive.
20
102 ÷ 3 = 34
1,000 x 3 = 3,000
32
15
75 ÷ 3 = 25
28 3s
140/18 = 7.7 recurring (that is, 7.7777...)
142 divided by 3 equals 47 with a remainder of 1.
8 of them, with 2 left over.