To find the number of 4-number combinations from the numbers 1 to 9, we use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of items to choose from and ( r ) is the number of items to choose. Here, ( n = 9 ) and ( r = 4 ). Thus, the number of combinations is ( C(9, 4) = \frac{9!}{4!(9-4)!} = \frac{9!}{4!5!} = 126 ). Therefore, there are 126 different 4-number combinations possible.
20
To find how many 4-digit numbers equal 19, we need to consider all combinations of four digits (ranging from 0 to 9) that add up to 19. However, since the maximum sum of four digits (9 + 9 + 9 + 9) is 36, the possible combinations are limited. There are no valid 4-digit numbers where the sum of the digits equals 19 while ensuring that the first digit is not zero. Therefore, the answer is that there are no valid 4-digit numbers that equal 19.
19
There are twenty numbers between 19 through 39, including 19 and 39. So the problem is 20 times 20 times 20 times 20 times 20. 320,0000
Some numbers that equal 19 include 19 itself, as well as combinations like 10 + 9, 15 + 4, and 25 - 6. Additionally, you could represent 19 as a fraction, such as 38/2 or as a decimal like 19.0. Other combinations, like 9.5 + 9.5 or 20 - 1, also equal 19.
20
To find how many 4-digit numbers equal 19, we need to consider all combinations of four digits (ranging from 0 to 9) that add up to 19. However, since the maximum sum of four digits (9 + 9 + 9 + 9) is 36, the possible combinations are limited. There are no valid 4-digit numbers where the sum of the digits equals 19 while ensuring that the first digit is not zero. Therefore, the answer is that there are no valid 4-digit numbers that equal 19.
19
There are twenty numbers between 19 through 39, including 19 and 39. So the problem is 20 times 20 times 20 times 20 times 20. 320,0000
Some numbers that equal 19 include 19 itself, as well as combinations like 10 + 9, 15 + 4, and 25 - 6. Additionally, you could represent 19 as a fraction, such as 38/2 or as a decimal like 19.0. Other combinations, like 9.5 + 9.5 or 20 - 1, also equal 19.
63
Infinitely many. 1 + 1 + 1 + 19 .1 + .1 + .1 + 21.7 .01 + .01 +.01 + 21.97 And so on. And all these are with three of the numbers being the same. There are also combinations where some numbers are irrational -infinite, non recurring decimals. Then there are combinations with some of the numbers being negative.
Assuming you are using "combinations" in the mathematical sense where order doesn't matter (if order does matter it would be "permutations"), there are 22C5 = 22!/5!17! = 26,334 possible combinations of 5 numbers from 22. They start {1, 2, 3, 4, 5}, {1, 2, 3, 4, 6}, {1, 2, 3, 4, 7}, ... and end ... {16, 19, 20, 21, 22}, {17, 19, 20, 21, 22}, {18, 19, 20, 21, 22}; I'll leave the 26,328 combinations in the middle for you to list.
The first number has 19 possibilities. The second has 18, and the third only 17. 19x18x17=5814 possible lock combinations. (If you could repeat, it would be 19x19x19=6859)
In addition, several pairs of numbers can equal 19. For example, 10 + 9 = 19, and 15 + 4 = 19. Additionally, 18 + 1 and 12 + 7 also sum to 19. Any two numbers that add up to 19 can be considered valid combinations.
71
Just one. When considering combinations, the order of the numbers makes no difference. So there is only one combination with those 7 numbers.